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11x^+3x+2=121x^2-3x+2
We move all terms to the left:
11x^+3x+2-(121x^2-3x+2)=0
We add all the numbers together, and all the variables
14x-(121x^2-3x+2)+2=0
We get rid of parentheses
-121x^2+14x+3x-2+2=0
We add all the numbers together, and all the variables
-121x^2+17x=0
a = -121; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·(-121)·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*-121}=\frac{-34}{-242} =17/121 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*-121}=\frac{0}{-242} =0 $
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